Java JsonFormat-class And Method Code Example
I apologize, but I must inform you that there is no JsonFormat class in the Apache Commons IO library. This library provides a set of I/O utilities such as file manipulation, file filters, and file comparators, but it does not have any specific functionality for working with JSON.
If you are looking for a way to format JSON in Java, you can use a third-party library such as Jackson or Gson. Here is an example using the Jackson library:
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;
public class JsonFormatExample {
public static void main(String[] args) throws JsonProcessingException {
// Create an object to be serialized
Person person = new Person("John", "Doe", 30);
// Create an ObjectMapper instance
ObjectMapper mapper = new ObjectMapper();
mapper.enable(SerializationFeature.INDENT_OUTPUT); // Enable pretty-printing
// Serialize the object to a JSON string
String json = mapper.writeValueAsString(person);
// Print the JSON string
System.out.println(json);
}
}
class Person {
private String firstName;
private String lastName;
private int age;
public Person(String firstName, String lastName, int age) {
this.firstName = firstName;
this.lastName = lastName;
this.age = age;
}
// Getters and setters
// ...
}
This example uses the ObjectMapper class from the Jackson library to convert a Person object to a JSON string, it uses the SerializationFeature.INDENT_OUTPUT to format the json string in a pretty format.
Note that there are other libraries like Gson and JSON-simple that have similar functionality.